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Home/ Questions/Q 4627380
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T03:33:34+00:00 2026-05-22T03:33:34+00:00

I have this propery in my entity class: @Column(name=avatar,nullable=false,length=1000) String getAvatarData() { return new

  • 0

I have this propery in my entity class:

@Column(name="avatar",nullable=false,length=1000)
String getAvatarData() {
    return new JSONObject(avatar.export()).toString();
}
void setAvatarData(String data) {
    avatar = Avatar.restore(new JSONObject(data).toMap());
}

Hibernate doesn’t handle it at all. At least, it’s not included in the schema it generates.

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  1. Editorial Team
    Editorial Team
    2026-05-22T03:33:34+00:00Added an answer on May 22, 2026 at 3:33 am
    @Access(AccessType.PROPERTY)
    

    on your entity. That’s JPA 2.0. For 1.0, use org.hibernate.AccessType:

    @AccessType("property")
    

    By the way, I would rather have a simple field with getters and setters, and annotate the field instead. Then, if you want custom transformations, add other methods, like getFooAsJSON

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