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Home/ Questions/Q 8135447
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T10:25:18+00:00 2026-06-06T10:25:18+00:00

i have this query but this shows column does not exist SELECT p.content, (select

  • 0

i have this query but this shows column does not exist

SELECT 
p.content,
(select count(*) from share_member WHERE username='pratik' AND share_id=share) as allow 
FROM posts p WHERE allow >="1"

and i got this error

Unknown column ‘allow’ in ‘where clause’

EDIT:
This edit has been done to improve sql query for my use

SELECT 
p.content,
CASE share_type 
WHEN 'public' then "1"
when 'lsit' then 
    (select count(*) from share_member WHERE username='pratik' AND share_id=share)
end as allow
FROM posts p WHERE allow=>1

Error code 1064, SQL state 42000

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T10:25:20+00:00Added an answer on June 6, 2026 at 10:25 am

    You cannot use column aliases in WHERE clause.

    You can, however, use HAVING clause instead, there you can use aliases. Difference being that WHERE is performed while constructing resultset, and HAVING is applied after the whole set is matched (which means in general, that HAVING is heavier).

    SELECT 
    p.content,
    (select count(*) from share_member WHERE username='pratik' AND share_id=share) as allow 
    FROM posts p
    HAVING allow >= 1
    

    EDIT: Your second query should look like this:

    SELECT p.content,
      CASE
        WHEN share_type='public' THEN "1"
        WHEN share_type='list' THEN (SELECT COUNT(*) FROM share_member WHERE username='pratik' AND share_id=share)
        END AS `allow`
    FROM posts p
    HAVING `allow` >= 1
    
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