Question

I have this query

$result = mysql_query("SELECT * FROM ship_data WHERE id = $ship") or die(mysql_error());
$rows = array();
while($r = mysql_fetch_assoc($result)) {
    $rows = $r; 
echo json_encode($rows);
}

And this bit of ajax to return the results

 $.ajax({
            type: "POST",
            dataType: "json",
            data: "ship=" + ship,
            cache: false,
            url: "/getdata.php",
            success: function (data) {
                alert(data.carrier);
            }
        });

If there is just one result in the array it works, if the array has multiple results in the array nothing is alerted.

Answer 1

Change your while loop to…

$rows = array();
while($r = mysql_fetch_assoc($result)) {
    $rows[] = $r;
}

echo json_encode($rows);

And your JavaScript should always iterate over data with $.each().