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Home/ Questions/Q 3979532
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T05:10:54+00:00 2026-05-20T05:10:54+00:00

I have this query: SELECT a.id, b.discount FROM (a LEFT JOIN b ON b.id_a

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I have this query:

SELECT a.id, b.discount FROM (a LEFT JOIN b ON b.id_a = a.id);

EXPLAIN command for this query is this:

id  select_type   table  type   possible_keys   key       key_len  ref    rows   Extra
1    SIMPLE        a      index  NULL            PRIMARY   4        NULL   1489   Using index
1    SIMPLE        b      ALL    NULL            NULL      NULL     NULL   819   

A is table with 1489 rows and B is a SQL view. Now I understand, that MySQL has to do 1489*819 operations which is way too not-optimized operation. If B was a table, I would create an index for column id_a, but I have no idea what to do with SQL view.

Anybody can help ?

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  1. Editorial Team
    Editorial Team
    2026-05-20T05:10:55+00:00Added an answer on May 20, 2026 at 5:10 am

    I would look at the view, and try to go to the raw tables that qualify the element you are concerned with finding exists or not. And ensure the root table of “b” view has an index on that key.

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