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Home/ Questions/Q 8553895
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T14:45:30+00:00 2026-06-11T14:45:30+00:00

I have this query: SELECT DATE( a.created_at ) AS order_date, count( * ) as

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I have this query:

    SELECT DATE( a.created_at ) AS order_date, count( * ) as cnt_order
    FROM `sales_order_item` AS a
    WHERE MONTH( a.created_at ) = MONTH( now())-1
    GROUP BY order_date

which will return result something like this (snapshot only otherwise will return per 31 days):

order_date  cnt_order 
2012-08-29  580
2012-08-30  839
2012-08-31  1075

and my full query is selecting based on above selection:

SELECT order_date
    , MAX(cnt_order) AS highest_order
FROM (
        SELECT DATE (a.created_at) AS order_date
            , count(*) AS cnt_order
        FROM `sales_order_item` AS a
        WHERE MONTH(a.created_at) = MONTH(now()) - 1
        GROUP BY order_date
    ) AS tmax

But it result :

order_date  highest_order
2012-08-01  1075

Which has the date wrong and always pick the first row of date where it suppose 2012-08-31. Maybe this is a simple error that I dont know. So how to get the date right point to 2012-08-31? Any help would be great.

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  1. Editorial Team
    Editorial Team
    2026-06-11T14:45:31+00:00Added an answer on June 11, 2026 at 2:45 pm

    You could try ordering the sub query result set; something like:

    SELECT
        DATE (a.created_at) AS order_date,
        COUNT(*) AS cnt_order
    FROM
        `sales_order_item` AS a
    WHERE
        MONTH(a.created_at) = MONTH(now()) - 1
    GROUP BY
        order_date
    ORDER BY
        cnt_order DESC
    
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