I have this query that retreives a list of id’s + NAME:
$sql = "SELECT id FROM #__table1 ";
$sql .= " WHERE (";
foreach($explode_tags as $k=>$explode_tag) {
$sql .= "name = ".$db->Quote(trim($explode_tag));
if(($k+1) != count($explode_tags))
$sql .= " OR ";
}
$sql .= ")";
$db->setQuery($sql);
$results = $db->loadResultArray();
The result is an array like this:
keywordID | NAME
1 cat
2 dog
3 horse
Now I have this table2:
id | ItemID | keywordID
1 4 1
2 4 2
3 4 3
4 6 1
5 6 2
6 7 1
I want to find from table2 all ItemID’s that have all keywordID’s found in table1.
In the example above I want to return only itemID 4 that has all keywords (all 3 of them).
I am running this query but I am not getting results:
...
$query .= " AND i.id IN (SELECT itemID FROM #__table2 WHERE (";
foreach($results as $k=>$result) {
$query .= "keywordID = ".(int)$result;
if(($k+1) != count($results))
$query .= " AND ";
}
$query .= "))";
UPDATE
Sorry, I miss read your question. I’ve done simple test using this data:
and using this query:
I can get the value that you wanted:
To achieve this, all you have to do is build the keywordID you want to use:
and then sort accending
the last step is, supply this array into query:
There you have it.