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Home/ Questions/Q 8107153
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T00:40:36+00:00 2026-06-06T00:40:36+00:00

I have this query, which is giving me some problems… I am trying to

  • 0

I have this query, which is giving me some problems…

I am trying to export a query into a text file, and this function creates a data.txt file but it is returned empty.

The error message i get is:

mysql_fetch_array(): supplied argument is not a valid MySQL result resource in …. on line 87

The code is:

$fh = fopen('data.txt', 'w');
$result1 = mysql_query("SELECT $checked FROM hostess;");
while ($row = mysql_fetch_array($result1)) {
    $last = end($row);
    foreach ($row as $item) {
        fwrite($fh, $item);
        if ($item != $last)
            fwrite($fh, "\t");
    }
    fwrite($fh, "\n");
}
fclose($fh);

The line 87 is:

while ($row = mysql_fetch_array($result1)) {

What is wrong with this?

Thanks..

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  1. Editorial Team
    Editorial Team
    2026-06-06T00:40:38+00:00Added an answer on June 6, 2026 at 12:40 am

    You should use mysql_error() while using mysql methods to trace the errors..

    Here even, you did not create the mysql connection. First add following lines in the starting of that code.

     $link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
     if (!$link) {
        die('Could not connect: ' . mysql_error());
     }
     mysql_select_db('db');
    

    Then run your code and don’t forget to use add mysql_error(). :):)

    $result1 = mysql_query("SELECT checked FROM hostess");
    if ( !$result1 ) { 
        echo mysql_error();
    }else{
         // your code
    }
    
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