Question

I have this query with multiple tables and I got the following result. Then I want to group by t.id. I know I can simply use group by t.id but how can I select the latest row of t.id which is url tw5.jpg and created_time 10000004

SELECT p.url,t.name,t.num_photo,t.id
FROM photos AS p
LEFT JOIN tag_maps AS tm ON p.id = tm.photo_id
LEFT JOIN tags AS t ON t.id = tm.tag_id

url                       created_time    name      num_photo  id
assets/img/tags/tw1.jpg   1000001         my house  1           1
assets/img/tags/tw2.jpg   1000002         dog       1           2
assets/img/tags/tw3.jpg   1000003         taiwan    2           3
assets/img/tags/tw5.jpg   1000004         taiwan    2           3

This is what i get when using group by t.id

url                       created_time    name      num_photo  id
assets/img/tags/tw1.jpg   1000001         my house  1           1
assets/img/tags/tw2.jpg   1000002         dog       1           2
assets/img/tags/tw3.jpg   1000003         taiwan    2           3

And this is what i want

url                       created_time    name      num_photo  id
assets/img/tags/tw1.jpg   1000001         my house  1           1
assets/img/tags/tw2.jpg   1000002         dog       1           2
assets/img/tags/tw5.jpg   1000004         taiwan    2           3

EDITED

Photos table

id    url                      created_time
1     assets/img/tags/tw1.jpg  1000001
2     assets/img/tags/tw2.jpg  1000002
3     assets/img/tags/tw3.jpg  1000003
4     assets/img/tags/tw5.jpg  1000004

Tags table

id name     num_photo
1  my house 1
2  dog      1
3  taiwan   2

Tag_maps

id   tag_id   photo_id
1    1        1
2    2        2
3    3        3
4    3        4

Answer 1

Edit #2: Without seeing sample data from each table or the table structures, I am guessing that the following will work:

SELECT p.url,
  created_time,
  t.name,
  t.num_photo,
  t.id
FROM photos p
LEFT JOIN tag_maps AS tm 
    ON p.id = tm.photo_id
LEFT JOIN tags AS t 
    ON t.id = tm.tag_id
INNER JOIN
(
  select max(created_time) MaxDate, t.id
  FROM photos p
  LEFT JOIN tag_maps AS tm 
      ON p.id = tm.photo_id
  LEFT JOIN tags AS t 
      ON t.id = tm.tag_id
  group by t.id
) d
  on p.created_time = d.MaxDate
  and t.id = d.id;

See SQL Fiddle with Demo

Or another way to write this is with a subquery that returns the max(photo_id) by tag_Id from the tag_maps table and use that result in the join:

SELECT p.url,
  created_time,
  t.name,
  t.num_photo,
  t.id
FROM photos p
INNER JOIN
(
  select max(photo_id) photo_id, tag_id
  from tag_maps
  group by tag_id
) AS tm 
    ON p.id = tm.photo_id
LEFT JOIN tags AS t 
    ON t.id = tm.tag_id

See SQL Fiddle with Demo

Result is:

|                     URL | CREATED_TIME |     NAME | NUM_PHOTO | ID |
----------------------------------------------------------------------
| assets/img/tags/tw1.jpg |      1000001 | my house |         1 |  1 |
| assets/img/tags/tw2.jpg |      1000002 |      dog |         1 |  2 |
| assets/img/tags/tw5.jpg |      1000004 |   taiwan |         2 |  3 |

Edit #1 since your url is different and you want the max(id), then you should be able to use:

SELECT p.url,
  t.name,
  t.num_photo,
  Max(t.id) id
FROM photos p
LEFT JOIN tag_maps AS tm 
    ON p.id = tm.photo_id
LEFT JOIN tags AS t 
    ON t.id = tm.tag_id
group by t.name, t.num_photo  

OP: You can use a subquery:

SELECT p.url,
    t.name,
    t.num_photo 
FROM
(
    select MAX(created_time) created_time, url, id
    from photos
    group by url, id
)  AS p
LEFT JOIN tag_maps AS tm 
    ON p.id = tm.photo_id
LEFT JOIN tags AS t 
    ON t.id = tm.tag_id

If the id value in the photos table is unique for each row, then you might need to use the following:

SELECT p1.url,
    t.name,
    t.num_photo 
FROM photos p1
inner join
(
    select MAX(created_time) created_time, url
    from photos
    group by url
)  AS p2
    on p1.url = p2.url
    and p1.created_time = p2.created_time
LEFT JOIN tag_maps AS tm 
    ON p1.id = tm.photo_id
LEFT JOIN tags AS t 
    ON t.id = tm.tag_id