Question

I have this question for you.I am working a function which has the whole address in one field.I am trying to separate it.I have started working on the one below and I am having difficulty when I try to work on the zip ,I want to test if there is a zip first at the end and if so I am trying to separate it from the state.Could you please have alook at it?Thanks alot guys as usual I appreciate you support..

      declare @var1 varchar(100)='1234 S.Almeda way,Seattle,WA9810'--just an example
        ,@u int
        ,@r int
        ,@var2 varchar(100)
        ,@var3 varchar(100)
        ,@Zip varchar(25)
        ,@var4 varchar(100)=null
             set @u = charindex(',', @var1)
             set @var2=rtrim(ltrim(substring(@var1, @u+1, 999)))
             set @r=CHARINDEX(',',@var2)
             set @var3=rtrim(ltrim(substring(@var2, @r+1, 999)))

             --set @var4=RIGHT(@var3,5)--not enough
             if (len(@var3)>=5 and ISNUMERIC(@var3)=1 )
             set  @var4=RIGHT(@var3,5)
             set rtrim(substring(@var3,1,len(@var3)-5))
             else set @var4=''

Answer 1

Here’s some sample code you can merge into yours

declare @var1 varchar(100)='1234 S.Almeda way,Seattle,WA9810'--just an example
declare @lastcomma int = len(@var1) - charindex(',', reverse(@var1)+',')
declare @lastPart varchar(100) = substring(@var1, @lastcomma+2, 100)
select @lastPart 
declare @zipstart int = patindex('%[0-9]%', @lastpart)
declare @zip varchar(5) = ''
if @zipstart > 0
    select @zip = substring(@lastpart, @zipstart, 5), @lastPart = rtrim(substring(@lastpart,1,@zipstart-1))
select @lastpart, @zip