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Home/ Questions/Q 8885777
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T21:23:38+00:00 2026-06-14T21:23:38+00:00

I have this regex: ‘/^files\/(.+\..+)$/’; But I want to replace the files/ section with

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I have this regex:

'/^files\/(.+\..+)$/';

But I want to replace the “files/” section with a runtime variable.

I tried this:

$filePath = "files/";
'/^'.$filePath.'(.+\..+)$/';

which didn’t work, as well as this:

$filePath = preg_quote("files/");
'/^'.$filePath.'(.+\..+)$/';

but I still get an error in this loop on the preg_match line, saying that “(” is an unknown modifier.

foreach (glob(FILE_PATH."*.*") as $filename) {
    preg_match($pattern, $filename, $matches);
    echo "<option class='file' value='".$matches[1]."'>".$matches[1]."</option>";
}

Any help would be appreciated, thanks.

EDIT

This works…

$filePath = 'files\/';

…but in actual usage, I’m trying to use a constant declared in another file.

So:

define('FILE_PATH', 'files/');

…and then trying to use that constant. It can’t have the escape character embedded because some other parts of the application need it without the escape character.

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  1. Editorial Team
    Editorial Team
    2026-06-14T21:23:40+00:00Added an answer on June 14, 2026 at 9:23 pm

    You need to hand preg_quote the delimiter:

    $filePath = preg_quote("files/", '/');
    

    Since you can use a lot of characters as delimiters, preg_quote cannot know, that you are going to use /, so it does not escape it by default. That’s what the second (optional) parameter is for.

    Otherwise, your second approach (the one using preg_quote) is the way to go.

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