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Home/ Questions/Q 8889343
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T22:14:20+00:00 2026-06-14T22:14:20+00:00

I have this regular expression: [^0-9!a-zA-z#\\$%&’\\*\\+\\-/=\\?\\^_`\\{\\|\\}~@\\.]+ and I am trying to split the email

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I have this regular expression:

[^0-9!a-zA-z#\\$%&'\\*\\+\\-/=\\?\\^_`\\{\\|\\}~@\\.]+

and I am trying to split the email address using

[Email]info@emerycommunications.com

But the following code in java:

String fileStr = "[Email]info@emerycommunications.com";

String invalidCharacters = "[^0-9!a-zA-z#\\$%&'\\*\\+\\-/=\\?\\^_`\\{\\|\\}~@\\.]+";

String[] tokens = fileStr.split(invalidCharacters);

for (String token:tokens) {
    if (token.contains("@")) {
        System.out.println(token);
    }
}

is giving this output:

[Email]info@emerycommunications.com

I am completely clueless as invalidCharacters variable covers [ and ] also.

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  1. Editorial Team
    Editorial Team
    2026-06-14T22:14:21+00:00Added an answer on June 14, 2026 at 10:14 pm

    You have A-z in your character class, and the square bracket characters come between upper case Z and lower case a in ASCII (and Unicode) order. Thus ] is being considered a valid rather than invalid character – presumably you meant A-Z instead.

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