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Home/ Questions/Q 7163407
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T13:53:54+00:00 2026-05-28T13:53:54+00:00

I have this script: $(document).ready(function() { $(‘#Checkout1’).addClass(‘disabled’); $(‘#voorwaarden’).change(function() { $(‘#Checkout1’).attr(‘disabled’, $(this).is(‘:checked’) ? null :

  • 0

I have this script:

$(document).ready(function() {
    $('#Checkout1').addClass('disabled');
    $('#voorwaarden').change(function() {
        $('#Checkout1').attr('disabled', $(this).is(':checked') ? null : 'disabled');
    });
});

The script is no change the attr disabled. But how can i change this script to this thing. When you change the #voorwaarden. Than remove the class diabled from #checkout1. And when i changed next the #voorwaarden. Than add class and going furter and furter. #voorwaarden is an checkbox.

Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T13:53:54+00:00Added an answer on May 28, 2026 at 1:53 pm

    Simply do with toggleClass()

    $(document).ready(function() {
        $('#Checkout1').addClass('disabled');
        $('#voorwaarden').change(function() {
            $('#Checkout1').toggleClass('disabled');
        });
    });
    

    Note: http://api.jquery.com/toggleClass/


    Edited: In case that you want to toggle ‘disabled’ property,

    $(document).ready(function() {
        $('#Checkout1').prop('disabled', true);
        $('#voorwaarden').change(function() {
            $('#Checkout1').prop('disabled', !$('#Checkout1').prop('disabled'));
        });
    });
    
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