Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8540503
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 11, 20262026-06-11T11:36:44+00:00 2026-06-11T11:36:44+00:00

I have this script in a view: <script type=text/javascript> $(document).ready(function() { $(#addbrand).click(function() { $.ajax({

  • 0

I have this script in a view:

<script type="text/javascript">
$(document).ready(function() {
    $("#addbrand").click(function() {
        $.ajax({
            url : '../brands/add',
            data : {
                name : "test",
                shortname : "tst"
            },
            dataType : 'json',
            success : function(html, textStatus) {
                alert('Success ' + textStatus + html);
            },
            error : function(xhr, textStatus, errorThrown) {
                alert('An error occurred! ' + errorThrown);
            }
        });
    });
});</script>

And in add controller I have these lines:

... else if($this->request->is('ajax')){
        if ($this->Brand->save($this->request->query)) {
            // How to send feedback!?
        }else{
            // How to send feedback!?
        }
        $this->autoRender = false;
        exit();
    }

When I click addbrand, Ajax operation runs successfully and a I can see the added row in database, but I don’t know how to send an error or success message to the user. I’ve read several tutorials but none of them were about cakephp2.0 while Everything is changed in 2.x.
I’ve also read JSON and XML views but unfortunately I didn’t understand anything!!!
I need to send a status code. If the status was OK then I ought to to send an array of Strings (brand names actually) and if status is not OK I should send a string that explains why the operation is not completed successfully.
I’d be most grateful if anybody can help me. Thanks


Update:

I changed the code. I used CakeResponse() and now my action is like this:

if($this->RequestHandler->isAjax()){
        if ($this->Brand->save($this->request->query)) {
            return new CakeResponse(array('body'=> json_encode(array('val'=>'test ok')),'status'=>200));
        }else{
            return new CakeResponse(array('body'=> json_encode(array('val'=>'test not ok')),'status'=>500));
        }
    }

Using CakeResponse I can handle the possible responses in Jquery well.

$("#addbrand").click(function() {
        $.ajax({
            url : '../brands/add',
            data : {
                name : "test",
                shortname : "tst"
            },
            dataType : 'json',
            success : function(data) {
              alert("The brand has been saved");
            },
            error : function(data) {
              alert("Eorror occured");
            },
            complete : function(data) {
                alert($.parseJSON(data.responseText).val);
            }
        });
    });

Although it seems to me that everything is working now and I can send several variables through the Ajax between client and server in JSON format, I need to know if it’s a standard way of sending Ajax responses in CakePHP or not? Is there any other simpler way for doing this?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-11T11:36:45+00:00Added an answer on June 11, 2026 at 11:36 am

    The following lines of code do exactly whatever return new CakeResponse(array('body'=> json_encode(array('val'=>'test ok')),'status'=>200)); does in my question:

    $this->set('val','test ok');
    $this->set('_serialize',array('val'));
    $this->response->statusCode(200);
    

    Remember that you need to do two important things:

    1. Add Router::parseExtensions('json'); to App/Config/routs.php.
    2. Add var $components = array("RequestHandler"); to your controller.

    I think this way is better because you don’t need to return anything. In previous solution we had to return cakeresponse object and this, sits uneasy with the nature of actions.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have this Javascript: <script language=javascript type=text/javascript> $().ready(function() { $('#ex2').jqm({ajax: 'view.php?id=<?=$objResult[id];?>', trigger: 'a.ex2trigger'}); });
I have the following jquery code in my view <script type=text/javascript> $(document).ready(function () {
I have this script $('head').append('<link rel=stylesheet href=css/file1.css type=text/css />'); $('head').append('<link rel=stylesheet href=css/jquery.jscrollpane.css type=text/css />');
I have this script that run to fix my menu bar to the browser
I have this script and need to be able to call the $play variable
I have this script set up that echoes all relevant users in a database
I have this script in the head of my index.html. I want different scripts
I have this script: #!/var/home/cherry/opt/perl use Test::More; use DBI; use Test::mysqld; use Data::Dumper; my
I have this script http://jsfiddle.net/gphp/ZMmRv/4/ I have two events: 1 - the div is
I have this script where I want to add an object to an array

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.