Question

I have this script in Ubuntu where I call the file load.php and I want to pass the argument $filexml

#!/bin/bash
...
filexml="/Program Files/myfile.xml"
./load.php $filexml

The file load.php is:

#!/usr/bin/env php
<?php
echo $_SERVER['argv']['params'][1];
exit;

But the result is incomplete because it takes the parameter until the space in /Program Files/ directory. Like this:

$/Program

Please help 🙂

Thanks!

Answer 1

Same solution as always.

./load.php "$filexml"