Question

🙂
I have this script, which find a users position taken from the number of credits.
It all works, but i have a little problem. If two users have the same credits, both of them will be on the same position.
Can I do, so if there are more users with same credits, then the system need to order by the users ID and out from that give them a position?

This is my code so far:

$sql = "SELECT COUNT(*) + 1 AS `number`
        FROM `users` 
        WHERE `penge` > 
                       (SELECT `penge` FROM `users` 
                        WHERE `facebook_id` = ".$facebook_uid.")";
$query_rang = $this->db->query($sql);

So if i have this:

ID -------- Credits

1  -------- 100

2  -------- 100

3  -------- 120

Then the rank list should be like this:

Number 1 is user with ID 3

Number 2 is user with ID 1

Number 3 is user with ID 2

Answer 1

$sql = "SELECT COUNT(*) + 1 AS `number` FROM `users` WHERE `penge` > (SELECT `penge` FROM `users` WHERE `facebook_id` = ".$facebook_uid.") ORDER BY COUNT(*) + 1 desc, users.ID";
$query_rang = $this->db->query($sql);

Later EDIT:

I don’t understand why you still have the same results….

I made a quick test. I have created a table:

Test: ID (Integer) and No (Integer)

I have inserted some values:

id  no
1   1
1   1
1   1
2   1
3   1
4   1
4   1
5   1

Now, if I run:

SELECT 
  id, COUNT(*) + 1 AS `number`
FROM
  test
GROUP BY
  id

I get:

id  number
1   4
2   2
3   2
4   3
5   2

But if I add ORDER BY:

SELECT 
  id, COUNT(*) + 1 AS `number`
FROM
  test
GROUP BY
  id
ORDER BY 
  count(*) desc, id

then I get:

id  number
1   4
4   3
2   2
3   2
5   2