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Home/ Questions/Q 561333
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T12:26:20+00:00 2026-05-13T12:26:20+00:00

I have this simple code that needs to get a chunk of a large

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I have this simple code that needs to get a chunk of a large log file that is being written into. At some point it stores the current location returned from
streampos start = istream::tellg();
method.
Later on the code has to read from the stream a buffer from the start till the end. The code is approximately like this:

streampos start = my_stream.tellg();

... // do some stuff with logging

streampos end = my_stream.tellg();
const streamsize size_to_read = (end - start);
char *buf = new char[size_to_read];

lock (m_logReadLock);
{
    my_stream.flush();
    my_stream.seekg(start);
    my_stream.read(buf, size_to_read);
    size_read = my_stream->gcount();
}
unlock (m_logReadLock);

The effect that I’m observing is that size_read is smaller than size_to_read and the stream has its eof flag set. Shouldn’t the end pointer specify exactly where the stream ends and read() method return that exact amount of data?
It is fine, I can work round it by checking the eof flag.
However, can anyone provide the explanation for this effect?

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-13T12:26:21+00:00Added an answer on May 13, 2026 at 12:26 pm

    http://groups.google.com/group/comp.lang.c++/browse_thread/thread/709cde3942e64d6c#

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