Question

I have this simple working curl command:

curl -k -d X-User=user -d X-Password=password https://12.12.12.21

This is my example:

import urllib2
opener = urllib2.build_opener()
opener.addheaders = [('X-User', 'user'),('X-Password', 'password')]
rr = opener.open("https://12.12.12.21")
print rr.read()

It’s not working as i expected ( result: wrong password/user name ), can you help me understand why?

Answer 1

Your curl command is using the -d flag which sends the data using POST, not using headers.

If you meant to use headers then you need to use the -H argument:

curl -k -H X-User=user -H X-Password=password https://12.12.12.21

Here is how to do a POST request in case that is what you need:

values = {'X-User' : 'user', 'X-Password' : 'password'}
data = urllib.urlencode(values)
req = urllib2.Request("https://12.12.12.21", data)
rr = urllib2.urlopen(req)