Question

I have this situation where I need to make a URL with a string that contains “.

For instance:

NSString *myStringWithURL = [NSString stringWithFormat: 
                             @"http://myurl.com/setParam.php?setName=
                             {\"name\":\"%@\"} ", name];
// myStringWithURL will return the desired URL but it is a String.
// of course I need it as URL in order to make the request.
NSURL *targetURL = [NSURL URLWithString : myStringWithURL]; 
                       //This will return nil. 

So the question is how to get my URL to not return nil?

The part {“name”:”My Name”} should be a JSON but this seemed simpler than using a NSDictionary and then using the parser of JSON and so on.

I thank you very much for your help!!

Answer 1

use stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding to convert your string