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Home/ Questions/Q 3957294
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T02:28:21+00:00 2026-05-20T02:28:21+00:00

I have this snippet: 1: if ((s >= kEnumValue1) && (s <= kEnumValue2)) {

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I have this snippet:

1: if ((s >= kEnumValue1) && (s <= kEnumValue2)) {
2:   MyObject * o = [self findObjectFor:s];
3:   if ([o isValidFor:self]) {
4:     [arrayOfMyObjects removeObject:o];
5:     for (MyObject * mo in arrayOfMyObjects) {
6:       ...
7:     }
8:   }
9: }

For some really weird reason, when my code reaches line 4, if I step over, it goes back to the start of the method on the same thread, without going thru lines 5-. Does anybody have any clue why this happens?

removeObject on NSMutableArray does not mention any exception.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T02:28:22+00:00Added an answer on May 20, 2026 at 2:28 am

    OK, after lots of debugging in all classes on my project, I found that, when MyObject’s release is called, it calls “release” on another class (since it is the last reference, it calls “dealloc”), once again for a third class, and then, it invokes removeObjectForKey:nil in NSMutableDictionary. This raises an NSInvalidArgumentException that is not logged at all. Way too evil…

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