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Home/ Questions/Q 871825
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T10:41:55+00:00 2026-05-15T10:41:55+00:00

I have this snippet of the code account.cpp #include account.h #include <iostream> #include <string>

  • 0

I have this snippet of the code

account.cpp

#include "account.h"
#include <iostream>
#include <string>  

using namespace std;

Account::Account(string firstName, string lastName, int id)
    : strFirstName(firstName), strLastName(lastName), nID(id) {}

void Account::printAccount(){
    cout << strFirstName;
}

account.h

#include <string>

using std::string;

class Account{
private:
    string strLastName;      //Client's last name
    string strFirstName;     //Client's first name
    int nID;                //Client's ID number
    int nLines;             //Number of lines related to account
    double lastBill;
public:
    Account(string firstName, string lastName, int id);
        void printAccount();
};

company.h

#ifndef CELLULAR_COMPANY_H
#define CELLULAR_COMPANY_H

#include <string>
#include <list>
#include <iostream>
#include "account.h"

using namespace std;

class Company {
private:
    list<Account> listOfAccounts;
public:
    void addAccount(string firstName, string lastName, int id) {
        Account newAccount(firstName, lastName, id);
        listOfAccounts.push_back(newAccount);
    }

    void printAccounts(){
        for(list<Account>::iterator i = listOfAccounts.begin(); i != listOfAccounts.end(); ++i){
            i.printAccount;           //here bug
        }
    }
};


#endif // CELLULAR_COMPANY_H

main.cpp

#include "cellularcompany.h"

int main(){
    Company newCompany;
    newCompany.addAccount("Pavel", "Nedved", 11111);
    newCompany.printAccounts();

    return 0;
}

can somebody please explain what does my error mean? thanks in advance (I have it in company.h see comment there)
I have bug 'struct std::_List_iterator<Account>' has no member named 'printAccount'

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T10:41:56+00:00Added an answer on May 15, 2026 at 10:41 am

    You forgot the parentheses after printAccount(). Otherwise, it’s not a method call. Also, you need to use the -> operator, since it’s an iterator.

    for(list<Account>::iterator i = listOfAccounts.begin();
        i != listOfAccounts.end(); ++i)
    { 
        i->printAccount();  // Note the ()!
        // This is equivalent to (*i).printAccount(); 
    } 
    
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