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Home/ Questions/Q 9193127
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T21:05:17+00:00 2026-06-17T21:05:17+00:00

I have this SQL: SELECT (Min(Time_In) & to & Max(Time_Out)) AS [Week Of], Round((Sum(DATEDIFF(n,

  • 0

I have this SQL:

SELECT (Min(Time_In) & " to " & Max(Time_Out)) AS [Week Of],
 Round((Sum(DATEDIFF("n", Time_In, Time_Out))/Count(DATEDIFF("n", Time_In, Time_Out))),2) AS [Avg Min of Jog]
FROM SomeTable
WHERE len(Time_In) > 0 AND len(Time_Out) > 0 
AND #01/01/2012# <= Time_In AND #12/31/2012# >= Time_In
GROUP BY DatePart('ww',Time_In);

Which picks out average times of a jog per week. I would also like to include a count how many times jogged per week, which I’m trying to do by counting the jog_id where SomeTable could have 5 entries for one jog_id.

I have tried:

SELECT (Min(Time_In) & " to " & Max(Time_Out)) AS [Week Of],
 Round((Sum(DATEDIFF("n", Time_In, Time_Out))/Count(DATEDIFF("n", Time_In, Time_Out))),2) AS [Avg Min of Jog],
 Count(distinct jog_id) AS [Num Jogs]
FROM SomeTable
WHERE len(Time_In) > 0 AND len(Time_Out) > 0 
AND #01/01/2012# <= Time_In AND #12/31/2012# >= Time_In
GROUP BY DatePart('ww',Time_In);

But this is giving me Syntax error (missing operator) in query expression 'Count(distinct jog_id)'.

What am I missing?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T21:05:18+00:00Added an answer on June 17, 2026 at 9:05 pm

    You can’t do this in Access without using a sub-query.
    EX:

    SELECT Count(*)
    FROM
    (SELECT DISTINCT Name FROM table1);
    

    Here is a detailed article on the topic:

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