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Asked: 2026-05-30T01:18:12+00:00

I have this string for example: str = my name is john#doe oh.yeh; the

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I have this string for example:

str = "my name is john#doe oh.yeh";

the end result I am seeking is this Array:

strArr = ['my','name','is','john','&#doe','oh','&yeh'];

which means 2 rules apply:

  1. split after each space ” ” (I know how)
  2. if there are special characters (“.” or “#”) then also split but add the characther “&” before the word with the special character.

I know I can strArr = str.split(” “) for the first rule. but how do I do the other trick?

thanks,
Alon

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1 Answer

  1. Editorial Team

    Assuming the result should be '&doe' and not '&#doe', a simple solution would be to just replace all . and # with & split by spaces:

    strArr = str.replace(/[.#]/g, ' &').split(/\s+/)

    /\s+/ matches consecutive white spaces instead of just one.

    If the result should be '&#doe' and '&.yeah' use the same regex and add a capture:

    strArr = str.replace(/([.#])/g, ' &$1').split(/\s+/)
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