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Home/ Questions/Q 7628085
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T05:32:53+00:00 2026-05-31T05:32:53+00:00

I have this string manipulation select product, CAST((LENGTH(currencies) – LENGTH(REPLACE(currencies, ‘*’, ”))) / LENGTH(‘*’)

  • 0

I have this string manipulation

select product,
       CAST((LENGTH(currencies) - LENGTH(REPLACE(currencies, '*', ''))) / LENGTH('*') AS UNSIGNED) AS currencies_count
  from MY_TABLE

to count “currencies” in a single field in this table

product       currencies
-----------   --------------
prod_name_1   *usd*cad*euro*
prod_name_2   *usd*cad*
prod_name_3   *usd*cad*euro*
prod_name_4   
prod_name_5   *usd*

The string manipulation returns a “+1” on all results (for exaple: prod_name_1, 4 currencies instead of 3). This because an external component store checkboxes data in this non-coherent manner (*usd*cad*euro* instead of *usd*cad*euro).

The point is that I can’t change the storage method of this component. There is a way to count the exact number of currencies in a field, ignoring the last “blank” value after the last ‘*’ separator?
How can I modify my string manipulation?

Getting crazy, any help will be very, very appreciated!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T05:32:54+00:00Added an answer on May 31, 2026 at 5:32 am

    The query above is not counting the empty part of the string after the final *. It’s not even splitting it at all. It’s simply saying that:

    *eur*usd*
    

    is 3 characters longer than

    eurusd
    

    To get the correct value I think you should just check for an empty currencies value, and if found then set the result to 0. Otherwise the result is the number of * symbols minus 1:

    SELECT
        CASE WHEN LENGTH(Currencies) = 0 THEN CAST(0 AS UNSIGNED) 
            ELSE CAST((LENGTH(Currencies) - LENGTH(REPLACE(Currencies, '*', ''))) / LENGTH('*') AS UNSIGNED) - 1 END AS currencies_count
    FROM MY_TABLE
    

    I don’t have a mysql database to to test that against but it should be OK.

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