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Home/ Questions/Q 6787621
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T17:23:17+00:00 2026-05-26T17:23:17+00:00

i have this structure for my new urls: module ApplicationHelper def product_path(product) unless product.category.nil?

  • 0

i have this structure for my new urls:

module ApplicationHelper
  def product_path(product)
    unless product.category.nil?
      cat = product.category
      if cat.ancestry_depth.eql?(2)
        product_long_path cat.root, cat.parent, cat, product
      else
        product_short_path cat.parent, cat, product
      end
    end
  end
end

routes.rb file

 get "/(*root_id)_(*subcategory_id)_(*category_id)_(*id)" => "products#show", :as => :product_long
  get "/(*root_id)_(*category_id)_(*id)" => "products#show", :as => :product_short

and my show action

  def show
    @product = Product.find_by_slug params[:id]
    cat = @product.category

    raise NotFound unless cat.slug.eql?(params[:category_id]) and cat.root.slug.eql?(params[:root_id])
    raise NotFound if cat.ancestry_depth.eql?(2) and !cat.parent.slug.eql?(params[:subcategory_id])
  end

How can i build up a redirect for "products/:id", i have products with 2 and 3 category depth.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T17:23:18+00:00Added an answer on May 26, 2026 at 5:23 pm

    I’m do it the most obvious way:
    ProductsController, show action

    @product = Product.find_by_slug params[:id]
    if @product.nil?
      @product = Product.find params[:id]
      redirect_to @product.redirect_string and return
    end
    

    in Product model

      def redirect_string
        if category.ancestry_depth.eql?(2)
          "/#{category.root.slug}_#{category.parent.slug}_#{category.slug}_#{slug}"
        else
          "/#{category.parent.slug}_#{category.slug}_#{slug}"
        end
      end
    

    But im not sure that this is most elegant solution, so im open for another solutions.

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