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Home/ Questions/Q 402377
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T17:07:10+00:00 2026-05-12T17:07:10+00:00

I have this structure <p class=descr> <span>something here</span> <img src=test /> </p> <p class=descr>

  • 0

I have this structure

<p class="descr">
  <span>something here</span>
  <img src="test" />
</p>

<p class="descr">
  <span>somthing else here</span>
  <img src="test2" />
  <img src="test3" />
</p>

so there can be more than one image inside of a <p> element.

What i need to do is loop through each <p> and then each <img> inside of it and add something to the front of it. Any help is appreciated. I tried doing an .each() but it’s not working.

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  1. Editorial Team
    Editorial Team
    2026-05-12T17:07:11+00:00Added an answer on May 12, 2026 at 5:07 pm

    Try this:

    $('p.descr > img').each(function() {
        // Make this code do what you want.
        $(this).prepend('<span>Prepended Content</span>');
    });
    

    The variable this represents the current image inside this function. In this example, I’m injecting a span element before each image inside a paragraph, but only direct descendant images.

    This function can be shortened if you’re only going to add another element before each image:

    $('p.descr > img').prepend('<span>Prepended Content</span>');
    
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