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Home/ Questions/Q 9118291
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T05:06:48+00:00 2026-06-17T05:06:48+00:00

i have this structure: struct dict{ int len; char (*dict0)[MAX_WORD_LEN+1]; char (*dict1)[MAX_WORD_LEN+1]; }; and

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i have this structure:

struct dict{
int len;
char (*dict0)[MAX_WORD_LEN+1];
char (*dict1)[MAX_WORD_LEN+1];

};

and i do this:

struct dict dictionary;
struct dict *p_diction=&dictionary;
but when i try to scanf with the pointer to pointer i get an error, naturally i is defined and everything.

scanf(“%10s”,p_diction->(*(dict0+i))[0]);

‘expected identifier before ‘(‘ token

and no i dont want to scanf using &dictionary, as this also happens in other instances besides scanf.

what is the correct form to write the command?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T05:06:50+00:00Added an answer on June 17, 2026 at 5:06 am

    What you want is

    p_diction->dict0[i]
    

    or

    *(p_diction->dict0 + i)
    

    You need to pass a pointer to char for the %s conversion, so the char[MAX_WORD_LEN+1] is okay (it will be converted to a pointer to the first char in it).

    p_diction->dict0
    

    gives you the pointer to the char[MAX_WORD_LEN+1], and you want the i-th of these arrays, so you must increment this pointer by i. Then to get the right type of pointer, you must dereference to get the array. Then you can either use the automatic array-to-pointer conversion, or explicitly pass the address of the first char in the array

    &p_diction->dict0[i][0]
    

    With the two dereferencings you attempted, you would have passed a char, which would cause havoc. You need only one.

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