Question

I have this structure:

var a = [];
a.push({"level": 1, "column": 4, "parent": "none", "title": "Node 0", "content": "Parintele suprem", "show": "1"});
var b = a;

a.push({"level": 1, "column": 5, "parent": "none", "title": "Node 1", "content": "Parintele suprem", "show": "1"});

console.log(b);

Now the problem is that b has the exact content as a (the content after the second push). This suggest (correct me if I’m wrong) that when I said b = a I actually gave b same reference as a, so whatever I do in a I have in b. The thing is that I need to pass the value. So I have the previews a, value in b.

Edit to make the question more clear: How do I pass the value instead of the reference?

Answer 1

I think you can use this to copy the value instead of the reference:

var b = a.slice(0);  

EDIT
As the comments have mentioned and it’s also mentioned here: https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Array/slice

slice does not alter the original array, but returns a new “one level deep” copy that contains copies of the elements sliced from the original array. Elements of the original array are copied into the new array as follows:

• For object references (and not the actual object), slice copies
  object references into the new array. Both the original and new array
  refer to the same object. If a referenced object changes, the changes
  are visible to both the new and original arrays.

• For strings and numbers (not String and Number objects), slice copies
  strings and numbers into the new array. Changes to the string or
  number in one array does not affect the other array.

If a new element is added to either array, the other array is not affected.