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Home/ Questions/Q 8822893
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T06:13:16+00:00 2026-06-14T06:13:16+00:00

I have this table… +—–+——–+——+—–+—–+ |categ| nAME | quan |IDUNQ| ID| +—–+——–+——+—–+—–+ | 1

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I have this table…

+-----+--------+------+-----+-----+
|categ| nAME   | quan |IDUNQ|   ID|
+-----+--------+------+-----+-----+
|   1 | Z      |    3 |   1 |  15 |
|   1 | A      |    3 |   2 |  16 |
|   1 | B      |    3 |   3 |  17 |
|   2 | Z      |    2 |   4 |  15 |
|   2 | A      |    2 |   5 |  16 |
|   3 | Z      |    1 |   6 |  15 |
|   3 | B      |    1 |   7 |  17 |
|   2 | Z      |    1 |   8 |  15 |
|   2 | C      |    4 |   8 |  15 |
|   1 | D      |    1 |   8 |  15 |
+-----+--------+------+-----+-----+

I need to get the Z of category 1 + Z of category 2 – Z of category 3

For example, (3+3-1) = 5 ==> 3 of cat 1, 3 of cat 2, 1 of cat 3

The final result should be…

Z ==> 5
A ==> 5
B ==> 2
C ==> 4
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T06:13:17+00:00Added an answer on June 14, 2026 at 6:13 am

    Note: I’m assuming the data for “C” from your example was mistakenly omitted.

    SELECT nAME, SUM(CASE categ WHEN 3 THEN 0-quan ELSE quan END) AS quan
    FROM theTable
    GROUP BY nAME
    

    SQL Fiddle

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