Question

I have this table where columns correspond to names:

i.e. 11 = first, 12 = second, 13 = third..

COLUMNID(string)  starttime(string) endtime(string) 

11                 20111203123132    20101203143239
11                 20101203143156     20101203143322
11                     ...               ...
12
12
13
14
16
17
18
18

I would need a query to give me names instead of ID

COLUMNAME(string)  starttime(string) endtime(string) 
FIRST                 20111203123132    20101203143239
FIRST                 20101203143156     20101203143322
FIRST                    ...               ...
FIRST
FIRST
SECOND
SECOND
THIRD
...

SOLUTION:

SELECT ID, USERID, ( CASE
WHEN SUBSTR(USERID,1,4) LIKE ‘CC0%’ THEN ‘ADMIN’
WHEN SUBSTR(USERID,1,4) LIKE ‘CC1%’ THEN ‘THEO’
WHEN SUBSTR(USERID,1,4) LIKE ‘CC12%’ THEN ‘PAT’
WHEN SUBSTR(USERID,1,4) LIKE ‘CC13%’ THEN ‘DOUG’
WHEN SUBSTR(USERID,1,4) LIKE ‘C22%’ THEN ‘PHIL’
WHEN SUBSTR(USERID,1,4) LIKE ‘K15%’ THEN ‘SONIA’
WHEN SUBSTR(USERID,1,4) LIKE ‘k16%’ THEN ‘JEAN’
WHEN SUBSTR(USERID,1,4) LIKE ‘P58%’ THEN ‘FAB’
WHEN SUBSTR(USERID,1,4) LIKE ‘P9%’ THEN ‘LOG’
ELSE ‘N/A’
END ) USERNAME
FROM LOG_HISTORY

Answer 1

This depends on what database type you are targetting. If you are targeting SQL Server, I would suggest exploring something like this

SELECT Name = 
   CASE COLUMNID
      WHEN '11' THEN First 
      WHEN '12' THEN Second
   END,
   starttime, endtime
FROM yourtable

You may want to look at your database design. I’m not sure what you curently have is the best to achieve the result you seem to want. Is there a reason starttime and endtime columns are strings instead of datetime?

Edit : Modified Query to match question update