Question

I have this tables in my DB:

“USERS”

id  email                      name             last_access
1   [e-mail]     Name1 Surname1      2012-10-05 13:58:19.0
2   [e-mail]     Name2 Surname2      2012-10-05 13:56:59.0
3   [e-mail]     Name3 Surname3      2012-10-05 13:57:57.0

“NETS_PERMISSIONS”

user_id     network_id     perm
1           1234           3
2           1235           3

Now, I have this query:

SELECT DISTINCT user.id, user.name, nets.network_id, nets.perm
FROM users as user LEFT OUTER JOIN nets_permissions AS nets
ON user.id = nets.user_id AND nets.perm <> 3 WHERE user.id!=1 AND nets.network_id=1234

The result query is empty, but instead I want that
– from the ‘nets_permissions’ table, are left out rows with perm=3 and user_id and network_id like spiecified in the query (in this case for ex. user_id=1 and network_id=1234): in this case the left part of the query is empty.
– from the ‘users’ table I want take every row but, if it isn’t in the ‘nets_permissions’ table, the rows have network_id and perm .

So, from this two tables, in this example, I would this result:

id    name             network_id    perm
2     Irene Pippo      <null>        <null>
3     Luca Niccolini   <null>        <null>

Thank you very much to all of you for your help.

Answer 1

This should give you what you want–only users who don’t have perm 3 and nework_id 1234

SELECT u.id, u.name, n.network_id, n.perm
  FROM users as u 
  LEFT JOIN nets_permissions as n
    ON u.id = n.user_id AND n.perm = 3 AND n.network_id=1234 
 WHERE n.network_id IS NULL