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Home/ Questions/Q 6602639
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T18:54:01+00:00 2026-05-25T18:54:01+00:00

I have this : template<class T, class U> class A { template<size_t N> void

  • 0

I have this :

template<class T, class U>
class A
{
    template<size_t N>
    void BindValues();
}

template<class T, class U>
template<size_t N>
inline void A<T, U>::BindValues()
{
    conn->setValue<N-1>( std::get<N-1>(m_Tuple) );
    BindValues<N-1>(conn);
}

template<class T, class U>
template<>
inline void A<T, U>::BindValues<1>()
{
    conn->setValue<0>( std::get<0>(m_Tuple) );
}

My Compile error is:

invalid explicit specialization before '>' token
enclosing class templates are not explicitly specialized
template-id BindValues<1> for void A<T, U>::BindValues() does not match any template declaration
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T18:54:02+00:00Added an answer on May 25, 2026 at 6:54 pm

    Unfortunately a template method inside a template class cannot be specialized just based on template argument of method.

    You need to specialize the template class also. In other words, the member method specialization should be a complete specialization with respect to class template (i.e. <T,U>) params as well as the member template params (i.e. <size_t>).

    For example, you may have to specialize something like this (demo):

    template<>  // <------ you have to specialize class also
    template<>
    inline void A<int, double>::BindValues<1>()  // <-------- see A<T,U>
    {
        ...
    }
    
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