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Home/ Questions/Q 908435
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T16:43:05+00:00 2026-05-15T16:43:05+00:00

I have this trial timer code to time euler solutions in Ruby. $RUNS =

  • 0

I have this trial timer code to time euler solutions in Ruby.

$RUNS = 12
def run(solve)
  times = []
  $RUNS.times do
    start_t = Time.now.usec
    solve.call
    end_t = Time.now.usec
    times << (end_t - start_t)/1000.0
  end
  #times = times.delete_if {|i| i < 0}
  puts times.inspect
  times.sort

  mean = times.inject{|a,c| a+c} / $RUNS
  puts("Mean:\t#{mean}");
  if (times.length % 2 == 0) then
    median = (times[times.length / 2 - 1] + times[times.length / 2]) / 2.0
  else 
    median = times[times.length / 2];
  end
  puts("Median: #{median}");

end

Unfortunately, I keep getting answers like this:

[409.805, 418.16, -582.23, 402.223, -581.94, 413.196, 426.816, -584.732, 519.457, -569.557, 558.918, -579.176]

What can I do to avoid these strange negative numbers?

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  1. Editorial Team
    Editorial Team
    2026-05-15T16:43:06+00:00Added an answer on May 15, 2026 at 4:43 pm

    usec returns the microseconds from the time in the same was as month returns the month. It is not the number of microseconds for the given time since the epoch.

    So if start_t was 1049896564.259970 seconds and end_t was 1049896592.123130 seconds then you would get 123130 – 259970 if you subtracted the usecs. i.e. a negative number.

    Instead you could use Time.now.to_f to convert to floating point number of seconds since epoch and subtract those from each other. You can also just subtract one Time object from another directly e.g.

    start_t = Time.now
    solve.call
    end_t = Time.now
    times << end_t - start_t
    
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