Home/ Questions/Q 6018081
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-23T03:13:21+00:00

I have this use case for which I am generating an image in the

  • 0

I have this use case for which I am generating an image in the getPost method of servlet.
I was saving the image in the local file system at /tmp/xyz.jpg and then doing something like 

response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("<html>");
out.println("<title>Example</title>");
out.println("<body><h2>Graph is :</h2>");
out.println("<img src='/tmp/TimeSeriesChart.jpg'></body>");
out.println("</html>");

Naturally the image did not get displayed when I hit the URL (to call servlet).

The reason I think was that img src is calculating against the Application’s Root not fileSystem’s Root.

So to summarize I want to be able to save the image at a proper place relative to Application Root , access the image and display it.

Q1. How to find the Application Root within the servlet. So that I can save the image rightly.

Q2. How advisable is to set the content as image and then read it as bytes and display :
http://www.exampledepot.com/egs/javax.servlet/GetImage.html

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    Ans1: ServletContext.getRealPath() will give you the app root location.

    Ans2: Nothing wrong in having a servlet, but Container doing that would handle the following cases as well:

    1. If-Modified-Since, sends SC_NOT_MODIFIED response
    2. Caching the image data in container for subsequent requests.
    • 0