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Home/ Questions/Q 8115577
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T03:31:09+00:00 2026-06-06T03:31:09+00:00

I have this (working) CPU code: #define NF 3 int ND; typedef double (*POT)(double

  • 0

I have this (working) CPU code:

#define NF 3
int ND;

typedef double (*POT)(double x, double y);

typedef struct {
    POT pot[NF];
} DATAMPOT;

DATAMPOT *datampot;

double func0(double x, double y);
double func1(double x, double y);
double func2(double x, double y);


int main(void)
{
    int i;

    ND=5;
    datampot=(DATAMPOT *)malloc(ND*sizeof(DATAMPOT));

    for(i=0;i<ND;i++){
        datampot[i].pot[0]=func0;
        datampot[i].pot[1]=func1;
        datampot[i].pot[2]=func2;
    }

    return 0;
}

Now I try a GPU version like this

#define NF 3
int ND;

typedef double (*POT)(double x, double y);

typedef struct {
    POT pot[NF];
} DATAMPOT;

DATAMPOT *dev_datampot;

__device__ double z_func0(double x, double y);
__device__ double z_func1(double x, double y);
__device__ double z_func2(double x, double y);

__global__ void assign(DATAMPOT *dmp, int n)
{
    int i;

    for(i=0;i<n;i++){
        (dmp+i)->pot[0]=z_func0;
        (dmp+i)->pot[1]=z_func1;
        (dmp+i)->pot[2]=z_func2;
    }

}

int main(void)
{
    int i;

    ND=5;
    cudaMalloc((void**)&dev_datampot,ND*sizeof(DATAMPOT));

    assign<<<1,1>>>(dev_datampot,ND);

    return 0;
}

but the assignment of device function pointers does not work.
Where is the mistake? And how it can be corrected?
Thanks you very much in advance.
Michele

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T03:31:10+00:00Added an answer on June 6, 2026 at 3:31 am

    Hope this will help someone

    #define NF 3
    int ND;
    
    typedef double (*POT)(double x, double y);
    
    typedef struct {
        POT pot[NF];
    } DATAMPOT;
    
    DATAMPOT *dev_datampot;
    
    __device__ double z_func0(double x, double y);
    __device__ double z_func1(double x, double y);
    __device__ double z_func2(double x, double y);
    
    //Static pointers to the above device functions    
    __device__ POT z_func0_pointer=z_func0;  
    __device__ POT z_func1_pointer=z_func1;
    __device__ POT z_func2_pointer=z_func2;
    
    
    
    int main(void)
    {
        int i;
        POT pot_pointer;
    
        ND=5;
        cudaMalloc((void**)&dev_datampot,ND*sizeof(DATAMPOT));
    
        for(i=0;i<ND;++i){  
         cudaMemcpyFromSymbol( &pot_pointer,z_func0_pointer, sizeof( POT ) );
      cudaMemcpy(&dev_datampot[i].pot[0]),&pot_pointer,sizeof(POT),cudaMemcpyHostToDevice);
    
         cudaMemcpyFromSymbol( &pot_pointer,z_func1_pointer, sizeof( POT ) );
      cudaMemcpy(&dev_datampot[i].pot[1]),&pot_pointer,sizeof(POT),cudaMemcpyHostToDevice);
    
         cudaMemcpyFromSymbol( &pot_pointer,z_func2_pointer, sizeof( POT ) );
      cudaMemcpy(&dev_datampot[i].pot[2]),&pot_pointer,sizeof(POT),cudaMemcpyHostToDevice);
        }
    
        return 0;
    }
    
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