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Home/ Questions/Q 8078865
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T15:55:41+00:00 2026-06-05T15:55:41+00:00

I have this WSO2 ESB proxy: <?xml version=1.0 encoding=UTF-8?> <proxy xmlns=http://ws.apache.org/ns/synapse name=sid008 transports=http startOnLoad=true

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I have this WSO2 ESB proxy:

<?xml version="1.0" encoding="UTF-8"?>
<proxy xmlns="http://ws.apache.org/ns/synapse" name="sid008" transports="http" startOnLoad="true" trace="disable">
    <target>
        <inSequence>

            <switch source="get-property('inquiryId')">
                        <log level="full"/>
                <case regex="">

                        <send/>

                </case>
                 <default>

                 </default>
             </switch>

        </inSequence>

        <outSequence>                      
<....some processing..>
            <send/>

        </outSequence>
    </target>
    <publishWSDL key="CommonService.wsdl">
        <resource location="request.xsd" key="request.xsd"/>
        <resource location="response.xsd" key="response.xsd"/>
        <resource location="SMEV.xsd" key="SMEV.xsd"/>
        <resource location="statusAndError.xsd" key="statusAndError.xsd"/>
    </publishWSDL>
</proxy>

In this proxy in default case doesn’t run outSequence without send mediator. How can I do it without send mediator

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  1. Editorial Team
    Editorial Team
    2026-06-05T15:55:42+00:00Added an answer on June 5, 2026 at 3:55 pm

    Try this config for :

    <default>
        <... some processing ...>
        <header action="remove" name="To"/>
        <property action="set" name="RESPONSE" scope="default" type="STRING" value="true"/>
        <send/>
    </default>
    

    With this config, you’ll send response to client directly from inSequence part (you won’t get into outSequence).

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