Question

I have this XML file:

<Response>     <errorCode>error Code</errorCode>     <errorMessage>msg</errorMessage>     <ResponseParameters>         <className>             <attribute1>a</attribute1>             <attribute2>b</attribute2>         </className>     </ResponseParameters> </Response> 

And I want the output to be:

<className>     <attribute1>a</attribute1>     <attribute2>b</attribute2> </className> 

My current XSL file is including also ‘ResponseParameters’ tag, which I do not want.

EDIT: note that the node className is dynamic. I do not know what will be this name at runtime.

<?xml version='1.0'?>  <xsl:stylesheet xmlns:xsl='http://www.w3.org/1999/XSL/Transform'     version='1.0'>      <xsl:output indent='yes' />      <xsl:template match='/'>         <xsl:copy-of select='//ResponseParameters'>         </xsl:copy-of>     </xsl:template> </xsl:stylesheet> 

Answer 1

Use :

<xsl:copy-of select='/Response/ResponseParameters/node()'/> 

The '//' abbreviation is very expensive (causes the complete XML document to be scanned), and should be avoided.