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Home/ Questions/Q 3454802
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T09:32:12+00:00 2026-05-18T09:32:12+00:00

I have this XML file which I parse into an ArrayList In this ArrayList

  • 0

I have this XML file which I parse into an ArrayList

In this ArrayList I have countries and the alarmnumbers for the countries in it.

I want to search to a country and get it’s police, ambulance or firedep. number.

Here is the code to help you out.

Parsing XML into ArrayList:

protected ArrayList<Alarmdiensten> getAlarmdiensten() {
     ArrayList<Alarmdiensten> lijst = new ArrayList<Alarmdiensten>();
     try {
      DocumentBuilder builder =DocumentBuilderFactory.newInstance().newDocumentBuilder();
      Document doc = builder.parse(getAssets().open("alarmdiensten.xml"));
      NodeList nl = doc.getElementsByTagName("land");
      for (int i=0;i<nl.getLength();i++) {
       Node node = nl.item(i);
       Alarmdiensten land = new Alarmdiensten();

                land.land = Xml.innerHtml(Xml.getChildByTagName(node, "naam"));
       land.landcode = Xml.innerHtml(Xml.getChildByTagName(node, "code"));
       land.politie = Xml.innerHtml(Xml.getChildByTagName(node, "politie"));
       land.ambulance = Xml.innerHtml(Xml.getChildByTagName(node, "ambulance"));
       land.brandweer = Xml.innerHtml(Xml.getChildByTagName(node, "brandweer"));
       land.telamba = Xml.innerHtml(Xml.getChildByTagName(node, "telamba"));
       land.adresamba = Xml.innerHtml(Xml.getChildByTagName(node, "adresamba"));

       lijst.add(land);
      }
     } catch (Exception e) {;
     }
     return lijst;
    }

The method that will use the alarmnumbers:

    public void AlarmMenu(){
     String landcode;
        ArrayList<Alarmdiensten> diensten = getAlarmdiensten();
     if(fakelocation = true) {
      landcode = sfakelocation;
     }
     else {
      try {
    landcode = getAddressForLocation(this, locationNow).getCountryCode();
   } catch (IOException e) {
    e.printStackTrace();
   }
     }

So I have the landcode, and I want to search in the ArrayList diensten for the numbers that belong with the landcode.

How can I do this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T09:32:12+00:00Added an answer on May 18, 2026 at 9:32 am

    Well at the moment you’ve got an ArrayList of Alarmdiensten objects. I would suggest you might want to change that to a Map so that you are storing a Map of land codes vs your Alarmdiensten objects.

    That way you get the Alarmdiensten out of the Map using the landcode and then simply call the getPolitie() etc methods on your Alarmdiensten object.

    I would make sure that you encapsulate your Alarmdiensten object BTW, accessing it’s private members directly is a bit of a no-no 🙂

    So something like:

    protected Map<String, Alarmdiensten> getAlarmdiensten()
    {
      Map<String, Alarmdiensten> alarmNumbersForCountries 
                                                 = new HashMap<String, Alarmdiensten>();
    
      try
      {
        DocumentBuilder builder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
        Document doc = builder.parse(getAssets().open("alarmdiensten.xml"));
        NodeList nl = doc.getElementsByTagName("land");
        for (int i = 0; i < nl.getLength(); i++)
        {
          Node node = nl.item(i);
          Alarmdiensten land = new Alarmdiensten();
    
          land.setLand(Xml.innerHtml(Xml.getChildByTagName(node, "naam")));
          land.setLandcode(Xml.innerHtml(Xml.getChildByTagName(node, "code")));
          land.setPolitie(Xml.innerHtml(Xml.getChildByTagName(node, "politie")));
          land.setAmbulance(Xml.innerHtml(Xml.getChildByTagName(node, "ambulance")));
          land.setBrandweer(Xml.innerHtml(Xml.getChildByTagName(node, "brandweer")));
          land.setTelamba(Xml.innerHtml(Xml.getChildByTagName(node, "telamba")));
          land.setAdresamba(Xml.innerHtml(Xml.getChildByTagName(node, "adresamba")));
    
          alarmNumbersForCountries.put(land.getLandCode(), land);
        }
      } 
      catch (Exception e)
      {
        // Handle Exception
      } 
      return alarmNumbersForCountries;
    }
    

    To get the entry out of the Map

    Alarmdiensten land = alarmNumbersForCountries.get(landcode);
    

    Another YMMV point is that you might want to split out the part of your method that builds Alarmdiensten objects from the XML parsing. “Each method should do one thing and one thign well.”

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