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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T19:36:13+00:00 2026-05-11T19:36:13+00:00

I have three classes: A data holder class CDataHolder, which uses a Pimpl pattern

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I have three classes:

  1. A data holder class CDataHolder, which uses a Pimpl pattern

    class CDataHolder
    {
    public:
      // ...
    private:
    friend class CBase;
    struct PImpl;
    PImpl* iPimpl;
    };
    
  2. A base class CBase, which need to access the iPImpl member in CDataHolder, so it is a friend class of CDataHolder

    class CBase: 
    {
    protected:
    CDataHolder::Pimpl* getDataHolderPimpl();
    };
    
  3. A derived class CDerived from CBase, which need to access the same iPimpl member also. Here occurs a problem.
    The derived class cannot use the iPimpl member although its parent class is a friend class. like this:

    class CDerived : public CBase
    {
    public:
    void doSth() {
       CDataHolder::Pimpl *pImpl = getDataHolderPimpl(); // this line raises an error: 
                                                         // "illegal access from CDataHolder to protected/private member CDataHolder::PImpl"
    }
    };
    

    There are plenty of derived classes, so it’s not a good way for each derived class to put a “friend class CDerivedXXX” line in CDataHolder class.
    How to overcome this issue? Is there a better way to do this? Thanks in advance.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T19:36:13+00:00Added an answer on May 11, 2026 at 7:36 pm

    Since you have declared struct PImpl in the private part of CDataHolder class, only friends of CDataHolder can access the same. Why don’t you put a forward declaration struct PImpl in the public section or even better before the CDataHolder class?

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