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Home/ Questions/Q 7751191
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T11:29:04+00:00 2026-06-01T11:29:04+00:00

I have three divs stacked on each other but offset so that a part

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I have three divs stacked on each other but offset so that a part of each div is visible. When one of the bottom divs is clicked I want the top div to animate out and back into the stack at the bottom, then the div that is clicked will appear at the top. So far I only have the code for when the middle div is clicked, but I cannot get it to work properly. What am I doing wrong? (I also realize that the code I wrote is probably terrible, this is the first jQuery code I have written.)

The css is very very simple:

    .first {
        z-index: 3;
    }
    .second {
        z-index: 2;
    }
    .third {
        z-index: 1;
    }

The basic html is this:

    <div class="first"></div>
    <div class="second"></div>
    <div class="third"></div>

Here is my code:

    $("div.second").click(function () {
        $("div.first").animate({
            left: "-=200px"},
            {duration: "fast",
            complete: function () {
                $("div.first").removeClass("first").addClass("third").animate({left: "+=350px", top: "+=60px"}, "fast");
            }
        });
        $("div.second").animate({
            left: "-=24px", top: "-=30px"},
            {duration: "fast",
            complete: function () {
                $("div.second").removeClass("second").addClass("first");
            }
        });
        $("div.third").animate({
            left: "-=24px", top: "-=30px"},
            {duration: "fast",
            complete: function () {
                $("div.third").removeClass("third").addClass("second");
            }
        });
    });

I can get the div.first to move to the side and back. But now I can’t get the classes to stay changed. What keeps happening is the div.second will remove it’s class and add .first in the animation, but when the animation is complete, it acts like it still has a class of .second.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T11:29:06+00:00Added an answer on June 1, 2026 at 11:29 am

    That coding style is very inefficient.

    Use something like this, It applies to every div

    $("div").click(function() {
       var first = $(".first");
       var fleft = first.css("left");
       var ftop = first.css("top");           
    
       var $this = $(this);
       var tLeft = $this.css('left');
       var tTop = $this.css('top');
       var tClass = $this.attr("class");
    
       first.animate({
          left: tLeft,
          top: tTop
       }).attr("class", tClass);
    
       $this.animate({
           top: ftop,
           left: fleft
       }).attr("class", "first");        
    
    });
    

    Demo

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