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Home/ Questions/Q 3391844
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T03:51:01+00:00 2026-05-18T03:51:01+00:00

I have three uiTableViews on a view. I have created three different NSMutableArray loaded

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I have three uiTableViews on a view.

I have created three different NSMutableArray loaded with different data.

I need to place one of the NSMutableArray as the datasource for one of the UITableView.

I am able to assign all three UITableViews datasource through the viewDidLoad of the form.

But what I really need to do, is assign each of the UITableView datasource to a different NSMutableArray.

How can I perform this task?

thanks
tony

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  1. Editorial Team
    Editorial Team
    2026-05-18T03:51:01+00:00Added an answer on May 18, 2026 at 3:51 am

    If all three UITableViews share the same datasource object (the object that holds all three of your arrays), then just use if statements to differentiate between the table views asking for the data:

    - (NSInteger)tableView:(UITableView *)tableView 
     numberOfRowsInSection:(NSInteger)section
    {
        // If table 1 is asking, give it table 1 data...
        if (tableView == myTableView1)
        {
            // Assume all sections have 3 rows each for
            // purposes of simple demonstration...
            return [dataSourceForTable1 count];
        }
    
        // If table 2 is asking, give it table 2 data...
        if (tableView == myTableView2)
        {
            // Assume all sections have 3 rows each for
            // purposes of simple demonstration...
            return [dataSourceForTable2 count];
        }
    
        // If table 3 is asking, give it table 3 data...
        if (tableView == myTableView3)
        {
            // Assume all sections have 3 rows each for
            // purposes of simple demonstration...
            return [dataSourceForTable3 count];
        }
    
       // The compiler will complain if we don't have
       // a final return since it's possible none of the 
       // if statements will be true ...
       return 0;
    }
    
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