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Home/ Questions/Q 8716695
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T06:08:49+00:00 2026-06-13T06:08:49+00:00

I have to count all the values in a matrix (2-d array) that are

  • 0

I have to count all the values in a matrix (2-d array) that are less than 200.

The code I wrote down for this is:

za=0   
p31 = numpy.asarray(o31)   
for i in range(o31.size[0]):   
    for j in range(o32.size[1]):   
        if p31[i,j]<200:   
            za=za+1   
print za

o31 is an image and I am converting it into a matrix and then finding the values.

Is there a simpler way to do this?

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  1. Editorial Team
    Editorial Team
    2026-06-13T06:08:50+00:00Added an answer on June 13, 2026 at 6:08 am

    The numpy.where function is your friend. Because it’s implemented to take full advantage of the array datatype, for large images you should notice a speed improvement over the pure python solution you provide.

    Using numpy.where directly will yield a boolean mask indicating whether certain values match your conditions:

    >>> data
    array([[1, 8],
           [3, 4]])
    >>> numpy.where( data > 3 )
    (array([0, 1]), array([1, 1]))
    

    And the mask can be used to index the array directly to get the actual values:

    >>> data[ numpy.where( data > 3 ) ]
    array([8, 4])
    

    Exactly where you take it from there will depend on what form you’d like the results in.

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