Question

I have to create a Regex for password validation which match

eg.

abcdABCD1234$%^

password must contains atleast two lowercase,two uppercase, two numeric and two special character. But they can give more than this criteria

Note- pattern should be inorder.

String pattern="(?=.*[a-z]{2,})(?=.*[A-Z]{2,})(?=.*[0-9]{2,})(?=.*[@#$%&]{2,})";

it is working for me but it is not checking order
means
AB uppercase or anycharacter should not come before ab (lowercase).

Does it clear for u.

     String minNum="4";
     String max="20";

     String REGEX="(^(?!.*(d))(?=.*[a-z]{3,})(?=.*[A-Z]{2,})(?=.*[0-9]{3,})(?=.[@#$%&*><?+]{2,})^(?!.*(#r)).{"+minNum+","+max+"})";
     //String regex="(?=.*[a-z]{2,})(?=.*[A-Z]{2,})(?=.*[0-9]{2,})(?=.*[@#$%&]{2,})";

      String INPUT ="acABC1333323@#";

   Pattern p = Pattern.compile(REGEX);

   Matcher m = p.matcher(INPUT);

   System.out.println(m.matches());

it is working correctly but when i am changing password
“ABac1333323@#”; it also matches but it is in correct according to my requirement, because AB is first order.

Answer 1

I think this is what you want

(?=[a-z]{2,}).{2,}(?=[A-Z]{2,}).{2,}(?=\d{2,}).{2,}(?=[@#$%&]{2,}).{2,}

It matches abcdABCD1234$%^ and abABcdCD1234$%^

It does not match ABababcdCD1234$%^ or ABac1333323@#

For two or more lower case followed by two or more upper case followed by two or more digits followed by two or more special characters, use :

[a-z]{2,}[A-Z]{2,}\d{2,}[@#$%&]{2,}