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Home/ Questions/Q 7367823
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T03:35:10+00:00 2026-05-29T03:35:10+00:00

I have to evaluate the following formula for permutations with repeated objects n!/(r1! *

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I have to evaluate the following formula for permutations with repeated objects

n!/(r1! * r2! * r3! * ......... * rn!)

wheren <= 500 and 1 <= ri <= 10 (there are n objects in total out of which r1 are alike of 1 kind , r2 are alike of 2nd kind and so on and the formula indicates the number of permutations of such objects).

I need an efficient coding solution for this because working with big integers in Java doesn’t prove to be fruitful for large cases.

Thanks in advance.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T03:35:11+00:00Added an answer on May 29, 2026 at 3:35 am

    You can do this in java by using

    public class Permutation
    

    designed to achieve a kind of your problem.

    See this link for your reference

    OR

    like this :

    private static Double calculatePermutationEntropy(List<Double> values, int baseOrder) {
     int valuesSize = values.size();
     if (baseOrder >= valuesSize + 1) {
       throw new RuntimeException("The size of the values is bigger than the order");
     }
    
     List<String> result = new ArrayList<String>();
     // iterate over the input
     for (int i = 0; i < valuesSize - baseOrder + 1; i++) {
       List<Double> neightbors = values.subList(i, i + baseOrder);
    
       List<Double> orderedValues = new ArrayList<Double>(neightbors);
    
       String window = "";
       for (int j = 0; j < neightbors.size(); j++) {
         // add the indexes in a string representation
         window += orderedValues.indexOf(neightbors.get(j));
       }
     result.add(window);
     }
     // use the shannon entropy calculation to get the result
     return calculateShannonEntropy(result);
    }
    

    source

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