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Home/ Questions/Q 7989583
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T12:47:36+00:00 2026-06-04T12:47:36+00:00

I have to find the most left digit in a randomly generated number (for

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I have to find the most left digit in a randomly generated number (for example: 46891 -> 4). No matter what the number is I keep getting zero. Here’s one of the codes I try:

int num1 = (int)((Math.random()*100000)+1);

while((Math.floor(num1/10))>0)
    {
        num1 = (int)Math.floor(num1/10);
    }

    System.out.println("Left digit: " + num1);

I tried to use Integer.parseInt, but I got this mistake, obviously: The method parseInt(String) in the type Integer is not applicable for the arguments (int).

What am I doing wrong and how can I make it work?

Thank you!

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  1. Editorial Team
    Editorial Team
    2026-06-04T12:47:37+00:00Added an answer on June 4, 2026 at 12:47 pm

    how about this :

    final Random r=new Random();
    final int t=r.nextInt(100000)+1;
    // naive way:
    final String s=Integer.toString(t);
    System.out.println("left digit is:"+s.charAt(0));
    // "math" way:
    int temp=t;
    while(temp>=10)
      temp/=10;
    System.out.println("left digit is:"+temp);
    
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