Question

I have to pass two arrays
1) that are filled with 1000 int’s between 0-100
2) that contains ten bins to sort the 1000 numbers.

How do I create the counter to sort numbers into ten bins such as 0-9, 10-19, 20-29, 30-39, 40-49,50-59 and so on to 90-99…

Would it be with an if/else that sorts them? If so, how do I add values into each bin? Would it be something like this?

This is what I have so far:

          //initialize array of 1000 elements
          int[] numbers = new int[1000];
          int i = 0;
          //initialize array of 10 bins
          int[] bins = new int[10];

          void setup() {
              // Populate array with random number
              for (int i = 0; i < numbers.length; i++) {
                 numbers[i] = ceil(random(0,99));
              }

           }

           //function that sorts random numbers into bins
           void counter(int[] numbers, int[] bins) {

           }

Answer 1

If you want every number from numbers in the right bin then I would use an array of 10 ArrayLists as the datastructure for your bins.

int[] numbers = new int[1000];
ArrayList[] bins = new ArrayList[10];

void setup() {
    for(int i = 0; i<bins.length; i++) {
        bins[i] = new ArrayList();
    }

    for (int i = 0; i < numbers.length; i++) {
        numbers[i] = floor(random(0,100));
    }
}

void counter(int[] numbers, ArrayList[] bins) {
    for (int i = 0; i < numbers.length; i++) {
        bins[floor(float(numbers[i])/10.0)].add(numbers[i]);
    }
}

You then get a bin with (for example the first bin consisting of numbers with values 0-9):

int sizeBin = bins[0].size();
for(int i=0; i<sizeBin; i++) {
    println(bins[0].get(i));
}

If you want the count of numbers in a bin you can get it with (again an example with the bin 0-9)

bins[0].size();