Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7278567
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 28, 20262026-05-28T22:53:31+00:00 2026-05-28T22:53:31+00:00

I have to rewrite code that references a 2-dimensional array using pointers instead of

  • 0

I have to rewrite code that references a 2-dimensional array using pointers instead of array operators.
How would I rewrite this:

...
else 
    array[i][j] = 'x';
...

So, I’m going to be setting the array to ‘x’ at that index. How would I do this with a pointer?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-28T22:53:31+00:00Added an answer on May 28, 2026 at 10:53 pm

    Assuming array is char array[x][y] then

     *(*(array + i) + j) = 'x';
    

    I mean, it’s ugly and I probably wouldn’t do that, but it will work.

    *(array + i)
    

    returns another char[] at index i. So, you then offset again into that using j. You can (should) break that up into a few lines so that it is easy to scan.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I'm trying to rewrite code I've written in matlab in C++ instead. I have
I have code that looks something like this: self.ui.foo.setEnabled(False) self.ui.bar.setEnabled(False) self.ui.item.setEnabled(False) self.ui.item2.setEnabled(False) self.ui.item3.setEnabled(False) And
I have code that looks something like this: self.ui.foo = False self.ui.bar = False
I have some legacy code that I'm rewriting using SubSonic to help the future
I have the basic code to rewrite a subdomain to another page. But how
I have this rewrite rule RewriteEngine On RewriteBase /location/ RewriteRule ^(.+)/?$ index.php?franchise=$1 Which is
Say I have a rewrite that needs to pass the url to a PHP
Quick one. I'm using mod rewrite and have most replacements in place: empty space
I have this long code about a table width some various content. It is
This partial code I hacked in to JamieMThomas's JQuery plugin that combines the Microsoft

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.