Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7667005
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 31, 20262026-05-31T14:59:08+00:00 2026-05-31T14:59:08+00:00

I have to simulate a client server UDP relationship by uploading files from the

  • 0

I have to simulate a client server UDP relationship by uploading files from the client to the server. It also uses a stop and wait protocol. My question is do I need to have code in my server class to handle corrupt packets? I read somewhere online that a **

UDP packet with a checksum error will be rejected by the stack. In
other words, it’s not possible for a UDP packet with a checksum error
to be “received at the other end correctly”, because the packet will
not be received at all.

**

Is that true? Would by server simply not receive the packet resulting in my client having a packet timeout?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-31T14:59:09+00:00Added an answer on May 31, 2026 at 2:59 pm

    UDP is a lossy protocol, it does not guarantee delivery of data. I imagine your simulation of a client server UDP relationship is a “best effort” (emulating the protocol itself) and so no, you would not need this extra code.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I need to perform a 3way stop and wait handshake between client and server
I have a class derived from Dictionary. I need this class to simulate a
I have a need to write an client-server application where a tiny server rests
I have a server that exposes its services over rpc and a client that
I have a vector of discrete data and I want to simulate from the
I have an server-application Foo that listens at a specific port and a client-application
I have simulated a browser client of socket.io in the node.js server I am
I have to simulate an array as if it was returned from Net::DBI fetchall_arrayref
I have to simulate family tree in prolog. And i have problem of symetrical
I have to simulate a game where each player has turns and needs to

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.