Question

I have to solve a small problem:
for a given array of chars,

char[] lista = {'a', '2', '?', 'd', '!', 'S', '3', 'D', 'k'}; 

I must:

1. Print only the vowels;
2. Print only the consonants;
3. Print the numbers and;
4. Print the others symbols.

I’m having problems in 4.

My code so far:

public class Teste {

    public static void main(String[] args) {
    char [] lista = {'a', '2', '?', 'd', '!', 'S', '3', 'D', 'k'};
    char [] vogal = {'a', 'e', 'i', 'o','u','A','E','I','O','U'};
    char [] numbers = {'1', '2', '3', '4', '5', '6', '7', '8', '9', '0'};
    char [] leters = {'b','c','d','f','g','h','j','k','l','m','n','p','q','r','s','t','v','w','x','y','z','B','C','D','F','G','H','J','K','L','M','N','P','Q','R','S','T','V','W','X','Y','Z'};
    char [] symbols = {'a', 'e', 'i', 'o','u','A','E','I','O','U','1', '2', '3', '4', '5', '6', '7', '8', '9', '0','b','c','d','f','g','h','j','k','l','m','n','p','q','r','s','t','v','w','x','y','z','B','C','D','F','G','H','J','K','L','M','N','P','Q','R','S','T','V','W','X','Y','Z'};

    for (char j=0; j<lista.length ; j++)
    for (char i=0; i<vogal.length ; i++ ){
    if ( vogal [i] == lista [j] )
    System.out.println( "the vowels are: " + vogal [i] );
    }

    for (char j=0; j<lista.length ; j++)
    for (char x=0; x<numbers.length ; x++ ) {    
    if ( numbers [x] == lista [j] )
        System.out.println( "the numbers are: " + numbers [x] );       
    }

    for (char j=0; j<lista.length ; j++)
    for (char y=0; y<leters.length ; y++ ) {    
    if ( leters [y] == lista [j] )
        System.out.println( "the leters are: " + leters [y] );       
    }
        //my main problem is here 
    for (char j=0; j<lista.length ; j++)
    for (char z=0; z<symbols.length ; z++ ){    
    if (symbols [z] != lista [j])
         System.out.println( "the symbols are: " + lista [j]); 
}
 }
    }

Any suggestion about how to print the symbols?
Thanks.

Answer 1

the inverse of

• print if at least one in the reference set (e.g. symbols) matches

is NOT

• print if at least one in the reference set does NOT match

but

• print if NONE in the reference set matches.

In other words, you should break the inner loop over z as soon as lista[j] is equal to symbols[z] and only print that it is a symbol once you have found no match in symbols.

(I’m not providing explicit code here as this is homework)