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Home/ Questions/Q 8936361
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T10:12:00+00:00 2026-06-15T10:12:00+00:00

I have to start a process in a cmd window. But in cases like

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I have to start a process in a cmd window.
But in cases like shown because of some error cmd window just flashes and I can’t see what happens. It would be the best if cmd window stay opened until some keypress or similar.

Dim q As String = Chr(34)
Dim p As New Process
With p.StartInfo
      .FileName = q & whereis7z & "\7z.exe" & q
      .Arguments = " e " & q & tempArch & fNameStr & q & " -y"
      .WindowStyle = ProcessWindowStyle.Normal
      .CreateNoWindow = False
      .WorkingDirectory = tempArch
       Debug.Print(.FileName & .Arguments)
End With
p.Start()
If p.ExitCode <> 0 Then
       MsgBox(p.ExitCode, MsgBoxStyle.Critical)
End If

Is here any way to keep cmd window opened until keypress to see what’s wrong with my ‘StartInfo’ because ‘ExitCode’ is not enough.

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  1. Editorial Team
    Editorial Team
    2026-06-15T10:12:01+00:00Added an answer on June 15, 2026 at 10:12 am

    Alternatively, you could redirect the standard output of the window in order to capture the program output.

    p.StartInfo.RedirectStandardOutput = True
    

    Then just read in what the program has output so you can display it yourself,

    Dim Output as String = p.StandardOutput.ReadToEnd
    
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