Question

I have to validate input field on the specific way:
This value must be divisible by proof value (can be integer or float). If there is an integer as result – OK, if the result is float – find the next smalles and biggest that can be divisible by this proof value.

I have following code at the Moment:

$("#calc").click( function(){
 var rlaenge = $("#rlaenge").val(); // is allways an integer
 var zEins = $("#zEins").val();
 var zZwei = $("#zZwei").val();
 var typeMath = <?php $_SESSION['typeMath']; ?>; // can be integer or float
 var erg = (parseFloat(rlaenge) - ((( parseFloat(zEins) + parseFloat(zZwei) ) / 2) * parseFloat(typeMath) )) / 2;
 var rlaengeCheck = rlaenge/typeMath;
 if (/^[0-9 ]+$/.test(rlaengeCheck)) {
  $("#result").value(erg);
 } else {

 //here the situation with findig off next biggest/next smallest  

 }          

});

I don’t have any Idea how to build such one issue with JavaScript.

I will be very grateful for any help with this case.

Alex.

Answer 1

well you can do this so:

rest = x % k;
base = x - rest;
next_devidable = base + k;
prev_devidable = base;

OLD

use Math methods

The floor() method rounds a number DOWNWARDS to the nearest integer, and returns the result

The ceil() method rounds a number UPWARDS to the nearest integer, and returns the result.

then check devision then ++, — the value if check not passed